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Alright, so let's go over the solution
to the unpacking challenge, we talked

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about in the last video. Currently, each
of the items in our albums list is a tuple.

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When we iterate over albums, we get
each tuple in turn, and we can unpack it

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at the same time. So the change is to
line ten, so let's make a change to line ten.

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So what I'm going to do is delete
the album part of the for album

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statement, and instead, what I'm going to
do is type in there, for name comma artist

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comma year, then leave the rest of
the line as it was, which was in albums.

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If we run the program now, we get the
same output as we did previously.

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So that's one solution. So you may have left
line ten alone, and instead, unpacked the

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tuples on the next line. What I'm going
to do is paste in this code, right after

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the existing code. Alright, so I'll come
down here and I'll paste in the code.

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So this will produce the same output. So
we'll run that firstly, to confirm that

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it is the case, and you can see we've got
the identical output there. Now it's not

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quite as efficient, compared to the
previous loop - the one starting on line ten -

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but it has the advantage that you also
have the original tuples available.

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Each time around the loop, you can refer to
album, if you need to. Most of the time,

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though, you should use the first loop,
where we unpack the tuples on line ten.

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Alright, so as well as showing you how
to unpack tuples, we've also seen

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that the items in a sequence, can be a
sequence type themselves. So here, our

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albums list contains tuples. Notice that
the list is homogeneous. All of the items

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it contains are of the same type. In other
words, here, they're all tuples. The tuples

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are heterogeneous - each one contains two
strings and an int.

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In the next version of this program, we'll make a change to add some songs to the albums.

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See you in the next video.