WEBVTT

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Let's try to solve a maximum problem.

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So we need to find the maximum number and between three variables.

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Let's assume that we have the number x required tool y equal to minus 4 and Z equal to 9.

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Well who's with the maximum number.

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He said this is equal to 9.

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You need to create the code only with your statement.

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And of course variables you can solve the problem with so many ways.

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The first one that pops up to my head is to make a properties.

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We see people who we can compare to the x y in the Y Z and the winner of the pairs we've comparing nodded

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to find the biggest number.

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So first we need to initialize the three vials X to Y equal minus 4 and Z equals nine.

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Now we can compare the X less than Y marks x y.

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You go to y of course else the maximum of X Y is equal to X..

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Then we compare the Y Z if y.

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Less than zet marks y z is equal to Z.

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X Marks y z is equal to y.

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Finally we will compare the results.

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If marks x y selected marks set then marks all his equal tool marks why zet else marks all is equal

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as tool marks x y.

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Finally we will be in various parts green marks.

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Finally we need to see here that there is out.

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Easier said than the sequel to 9 bill correct.

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We can taint the why and second 15.

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NOW 15.

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RJ this seems pretty good.

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Let's try to create something better.

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And they did assume that the first number is the maximum number some marks.

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All is equal to x and then tick with the other numbers.

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If this is true.

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Fresh willingness to lie 6 equal to 22 whites equal to 12 and Z equal to 25.

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First we will initialize Max.

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All you see is what works.

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Then read compare.

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If marks are less than Y then the marks.

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All is of course from now one is equal to Y and he marks all is less than z.

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From now on Max.

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All is equal opposite here.

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Here we forget the columns as well.

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One little of it is out.

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Also we forget to all print the result so print marks on.

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Of course it is correct.

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There's a sequel to minus one.

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So there is an extended tool.

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Okay this seems fine.