WEBVTT

00:00.270 --> 00:03.930
In this problem that we first create his own nurture your numbers.

00:03.930 --> 00:10.580
So when you do ask him about the size of the numbers in the actual numbers of the ARI.

00:12.550 --> 00:21.520
For that we will create a for loop at Aints from zero to and in every one of them we will read a value

00:21.520 --> 00:25.670
from the user then these value will be saved to the RV.

00:27.410 --> 00:30.700
After this process we need to calculate the maximum number.

00:30.740 --> 00:37.090
If you remember from the variables part of this cause the idea here is to initialize random value as

00:37.100 --> 00:37.810
maximal.

00:37.910 --> 00:46.940
So Max is equal to these number and then scan every other number to check if this is larger than these

00:46.940 --> 00:47.360
one.

00:47.360 --> 00:51.100
If you d make these number of marks you ended up with this process.

00:51.800 --> 00:53.950
First the input of the user.

00:55.660 --> 00:59.460
And then the we willingly celie's the least without any numbers.

00:59.460 --> 01:00.660
The follow up.

01:02.000 --> 01:05.870
That ain't zero tool in the JR.

01:05.910 --> 01:11.020
And as always we will get at the employer and value these value is in the end.

01:11.090 --> 01:14.810
We will have an input from the user number for these or something.

01:14.900 --> 01:22.570
Then add a dot up then of the temporarily riu that we already calculate or get from the user.

01:22.670 --> 01:31.200
So let's right we need five numbers and these numbers are 2 5 6 1 minus 2.

01:31.250 --> 01:32.630
Okay this seems right.

01:32.660 --> 01:39.860
Then we will initialize the maximal number that this equal to the first point of the three then four.

01:39.890 --> 01:47.600
I mean that ain't again from one because we already did something to the zero and then to the indigent

01:47.810 --> 01:49.190
end as always.

01:49.190 --> 01:53.720
Now if Maxy is less than add a.

01:53.870 --> 02:00.650
So this particular point is a good read there than the maximum value then for an hour on their maximum

02:00.650 --> 02:05.070
value is equal to this particular point or the RG without a way.

02:05.090 --> 02:07.840
We will always have the one part of that.

02:07.910 --> 02:11.960
Ari lets try to bring the maximum.

02:12.560 --> 02:18.940
So again we have sitting numbers that is you know minus five and 10.

02:19.370 --> 02:20.000
Okay.

02:20.030 --> 02:22.350
The result seems pretty good.